(3y^2-4y+1)/(y-2)

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Solution for (3y^2-4y+1)/(y-2) equation: 


D( y )

y-2 = 0

y-2 = 0

y-2 = 0

y-2 = 0 // + 2

y = 2

y in (-oo:2) U (2:+oo)

(3*y^2-(4*y)+1)/(y-2) = 0

(3*y^2-4*y+1)/(y-2) = 0

3*y^2-4*y+1 = 0

3*y^2-4*y+1 = 0

DELTA = (-4)^2-(1*3*4)

DELTA = 4

DELTA > 0

y = (4^(1/2)+4)/(2*3) or y = (4-4^(1/2))/(2*3)

y = 1 or y = 1/3

(y-1/3)*(y-1) = 0

((y-1/3)*(y-1))/(y-2) = 0

( y-1/3 )

y-1/3 = 0 // + 1/3

y = 1/3

( y-1 )

y-1 = 0 // + 1

y = 1

y in { 1/3, 1 }

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